WebUsing a calculator, we find that r ≈ 216.94 miles. Finally, we can find the circumference of the asteroid by using the formula: C = 2πr Substituting in our value of r, we get: C = 2π(216.94 miles) ≈ 1362.4 miles Therefore, the circumference of the asteroid is approximately 1362.4 miles. 4. Compare and contrast arguments for and against the … WebJan 21, 2024 · So, Earth's orbit is the circumference of a circle. The distance from Earth to the sun — called an astronomical unit — is 92,955,807 miles (149,597,870 kilometers), …
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WebTranscribed Image Text: According to Lunar Laser Ranging experiment the average distance LM from the Earth to the Moon is approximately 3.91 x 105 km. The Moon orbits the Earth and completes one revolution relative to the stars in approximately 27.5 days (a sidereal month). Calculate the orbital velocity of the Moon in m/s. WebApr 7, 2024 · The surface area of Titan is 83,305,418.53 Km^2. The surface gravity of the Titan is 1.354 m/s². For comparison, the Earth's surface gravity is 9.807 m/s². The larger an object is, the stronger the surface gravity is. The Mean Orbit Velocity (M.O.V.) is the speed at which it orbits is 20051.20 km/h. The average distance of the object from its ... north carroll soccer club hampstead md
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WebApr 10, 2024 · Inner Jupiter Moon Moon Group. The Jupiter Inner Moon Group are a small group of four moons that orbit close to the planet. The biggest of the group is Amalthea which the group is usually named after. ... Equatorial Circumference (km) 135.1: Surface Area (km^2) Surface Gravity (m/s²) 0.017: Mean Orbit Velocity (km/h) 113594.30: … WebNov 21, 2013 · But I can't seem to find the radius/circumference anywhere. Cute question, but: add the moon's position relative to earth to the earth's position relative to the sun and Bob's yr uncle. We can measure can find the distance that the moon loops around the earth and then since the moon orbits the earth once every 27-28 days then we multiply by 12. WebThe orbit of the Moon is a nearly circular ellipse about the Earth (the semimajor and semiminor axes are 384,400 km and 383,800 km, respectively: a difference of only 0.16%). The equation of the ellipse yields an eccentricity of 0.0549 and perigee and apogee … how to reset ipv4 address windows 10